I couldn’t find any working parameters as lambda x: -x or reverse=True in sort() function. Are there any possible solution? Already, I prefer the following method: fn main() raises: var numbers: List[Int]= [11, 3, 19, 1, 15, 4, 7] sort(numbers) print("Sorted in ascending order: ", numb…

At last, I found the solution as christoph_schlumpf mentioned: fn main() raises: fn cmp_fn(a: Int, b: Int) capturing -> Bool: return a > b var numbers: List[Int]= [11, 3, 19, 1, 15, 4, 7] sort[cmp_fn](numbers) print("Sorted in descending order: ", numbers)

Maybe you can add a cmp_fn parameter that does a descending comparison. sort[cmp_fn=…](numbers).

Maybe it is better to leave the sorted list as is, and print the elements in reverse: fn main() raises: var numbers: List[Int]= [11, 3, 19, 1, 15, 4, 7] sort(numbers) print("Sorted in ascending order: ", numbers) # print("Sorted in descending order: ", numbers[::-1]) # Caution! …

Can we sort elements in descending order in mojo?

Mojo

christoph_schlumpf (Christoph Schlumpf) February 21, 2026, 4:07pm 2

Please be aware that numbers[::-1] copies the list. See List slicing inconsistency

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Can we sort elements in descending order in mojo?

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