I couldn’t find any working parameters as lambda x: -x or reverse=True in sort() function. Are there any possible solution? Already, I prefer the following method: fn main() raises: var numbers: List[Int]= [11, 3, 19, 1, 15, 4, 7] sort(numbers) print("Sorted in ascending order: ", numb…

At last, I found the solution as christoph_schlumpf mentioned: fn main() raises: fn cmp_fn(a: Int, b: Int) capturing -> Bool: return a > b var numbers: List[Int]= [11, 3, 19, 1, 15, 4, 7] sort[cmp_fn](numbers) print("Sorted in descending order: ", numbers)

Maybe you can add a cmp_fn parameter that does a descending comparison. sort[cmp_fn=…](numbers).

Maybe it is better to leave the sorted list as is, and print the elements in reverse: fn main() raises: var numbers: List[Int]= [11, 3, 19, 1, 15, 4, 7] sort(numbers) print("Sorted in ascending order: ", numbers) # print("Sorted in descending order: ", numbers[::-1]) # Caution! …

Can we sort elements in descending order in mojo?

Mojo

christoph_schlumpf (Christoph Schlumpf) February 21, 2026, 4:07pm 2

Please be aware that numbers[::-1] copies the list. See List slicing inconsistency

Topic		Replies	Views
Interval not implementing 'Comparable' trait Mojo discussion	4	161	December 20, 2025
Proposal: Add radix sort to std lib Mojo	6	271	December 30, 2025
Cannot append list to list of lists Mojo mojo-compiler	3	85	March 12, 2026
How to reverse data using SIMD in Mojo Mojo discussion , 24_5 , docs	1	245	June 12, 2025
How to iterate over a compile time `List`/`Tuple` in Mojo Mojo docs	1	102	June 7, 2025

Can we sort elements in descending order in mojo?

Related topics